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3 Answers
- The WolfLv 61 decade agoFavourite answer
let M = molar mass
M(Al2(SO4)3)
= 2x26.98 + 3x(32.07 + 4x16.00)
= 342.17
and
M(S) = 32.07
but there are 3 moles of S in each mole of Al2(SO4)3
so
3M(S) = 96.21
then
%sulfur = (96.21/342.17) x 100% = 28.12%
the end
.
- Anonymous1 decade ago
the total molar mass of aluminum sulfide grams of Al times 2, plus grams of S times 3, plus grams of O times 12= molar mass of aluminum sulfide / the mass of S in the compound (mass of S in the compound is the number of grams in S, found in the periodic table, times 3) and then divide that number by the molar mass, and multiply that number by a hundred
- 1 decade ago
you find the molar mass of aluminum sulfide (grams of Al times 2, plus grams of S times 3, plus grams of O times 12= molar mass of aluminum sulfide) then, divide the mass of S in the compound (mass of S in the compound is the number of grams in S, found in the periodic table, times 3) and then divide that number by the molar mass, and multiply that number by a hundred, and voila :]
Source(s): hope i helped
