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Chemistry Help?
Determine the empirical formula for a compound that is 36.86% N and 63.14% O by mass.
A) NO2 B) NO3 C) N2O3 D) N2O E) NO
2 Answers
- 1 decade agoFavourite answer
N2O3
since they only give you the percent assume there is 100g of the substance and that makes the percents the number of grams of each substane. Then find the moles of each substance.
36.86gN/14.01gN = 2.6 moles N
63.14gO/16.00gO = 4 moles O
then you divide each moles by the smallest one
2.6/2.6 = 1mole N
4/2.6 = 1.5 mole O
since 1.5 isnt extremely close to the next whole number you multiply both by 2 and get
1 x 2 = 2 moles N
1.5 x 2 = 3 moles O
hence N2O3
- Anonymous1 decade ago
but wait.....you need to try to do your homework..people cant do it for you.i can only help.....no one did mine for me......
