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Giulio M
Lv 5
Giulio M asked in Science & MathematicsChemistry · 1 decade ago

Chemistry help?

How many atoms of oxygen are contained in 47.6 g of Al2(CO3)3? The molar mass of Al2(CO3)3 is 233.99 g/mol.

2 Answers

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  • Dr.A
    Lv 7
    1 decade ago
    Favourite answer

    Moles Al2(CO3)3 = 47.6 g / 233.99 = 0.203

    Al2(CO3)3 >> 2 Al3+ + 3CO32-

    Moles CO32- = 3 x 0.203 = 0.609

    Moles O = 3 x 0.609 = 1.83

    Atoms = 1.83 x 6.02x10^23 = 1.10x10^24

  • Melissa Me
    Lv 7
    1 decade ago

    47.6 / 233.99 g/mol to get moles of the compound...

    Then, you make a ratio and basically multiply by the number of moles of oxygen in the compound. I won't tell you how many that is though, I'm sure you're smart enough that you can do that little piece of multiplication.

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