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- 1 decade agoFavourite answer
pH + pOH =14
pOH= 14-7.4=6.6
pOH=-log[OH-]
[OH-]=2.5E-7M=[HCN]
KaxKb=1.0E-14
Kb= 1.0E-14/4.93E-10=2E-5
NaCN ---> Na+ + CN-
CN- + H2O <=> HCN.....+.... OH-
xM.................2.5E-7M.....2.5E-7M
Kb=[HCN][OH-]/[CN-]
2E-5=2.5E-7x2.5E-7/[CN-]
[CN-]=3.1E-9M
M=n/L
3.1E-9=n/10
n=3.1E-8moles CN-= moles NaCN
grams NaCN=3.1E-8x51=159.38g
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