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Limits......... help?
Find the limit as x->infinity of [(x^2) - 4] / [(x+3)(x-4)]
Please show the steps so i can understand...
2 Answers
- mohanrao dLv 71 decade agoFavourite answer
Apply L'Hopital's rule twice.
lim x-->∞ [ x^2 - 4] /[(x + 3)(x - 4)]
lim x-->∞ d [x^2 - 4] /d[(x+3)(x-4)] ----------------------d stands for derivative
lim x-->∞ [2x ]/(x+ 3 + x - 4)
limx-->∞ (2x) / (2x -1)
lim x-->∞ d(2x) /d(2x-1)
= 2/2
= 1
- sahsjingLv 71 decade ago
limit as x->infinity of [(x^2) - 4] / [(x+3)(x-4)]
= limit as x->infinity of x^2 / x^2
= 1
--------
Ideas: Neglect lower degree terms as x->infinity.
