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What is the graph of xy = 3y?
(A) one point
(B) two points
(C) one line
(D) two lines
(E) a right angle
Please do not give your method of solution -- just indicate A, B, C, D, or E.
9 Answers
- HemantLv 71 decade agoFavourite answer
Ans. (E) a right angle.
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EDIT :
For a Multiple Choice Question, the option which
is broadest in meaning is given the credit when only
one option is to be chosen.
The equation xy = 3y, i.e., y(x-3) = 0 does represent 2 lines
having separate equations y = 0 and x = 3. But that is only
the basic import of the question.
Since the line y=0 ( X-axis, a horizontalal line ) and the line
x = 3 ( parallel to Y-axis, a vertical line ) are at right
angles, it stands to reason that, in addition to being two
lines, they have something more : that they can be viewed
as being the two Arms of a Right Angle whose Vertex is at
the point ( 3, 0 ).
Hence, a broader interpretation of the equation xy = 3y
is given by the option : (E) a right angle.
So no matter how many TDs I am given,
I stand by my answer.
.........................................................................................
P.S. : Although I don't ' administer ' TDs,
. . . . I have always been at the receiving end.
..........................................................................................
EDIT - 2
[ If we are going to be so analytical mathematically,
then I will be equally analytical linguistically. ]
Of course, I was aware of the 4 right angles.
I also noted the indefinite article ' a ' in option (E)
which said " ' a ' right angle ", indicating 'any' one of the
four.
If it had said " ' the ' right angle ", then the option would
have been wrong.
As the things stand, I too remain convinced that
" ' a ' right angle " is the Most Correct of the options given.
...........................................................................................
- Anonymous1 decade ago
I don't know why previous answers of 2 lines have got thumbs down because they are correct.
xy = 3y ----> y = 0 or x = 3
EDIT. Comment to Hemant. A right-angle would imply two half lines or rays emanating from a point. It is true that the two lines in my answer are perpendicular, but one could argue that they make four right-angles at their intersection.
I remain convinced that two lines is the most correct of the options given.
EDIT 2. O.K. Let's agree to disagree.
- Anonymous5 years ago
take the derivative: 3x^2dx + y^2dx + 2xydy - 3dy = 0\ solve for dy/dx: (3x^2 + y^2)dx + (2xy - 3)dy = 0 dy/dx = - (3x^2 + y^2) / (2xy - 3) substitute in (2,-1): dy/dx = - (12 + 1) / (-4 - 3) dy/dx = 13/7 equation of the tangent line in point slope form: y + 1 = 13/7 (x - 2)